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2443313014193 is a prime number
BaseRepresentation
bin100011100011100000110…
…011011110010110110001
322122120121200111022112202
4203203200303132112301
5310012401112423233
65110235325232545
7341344400644262
oct43434063362661
98576550438482
102443313014193
11862226554887
12335644702755
13149532442a9c
1486385226969
1543852181be8
hex238e0cde5b1

2443313014193 has 2 divisors, whose sum is σ = 2443313014194. Its totient is φ = 2443313014192.

The previous prime is 2443313014111. The next prime is 2443313014199. The reversal of 2443313014193 is 3914103133442.

2443313014193 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2297792127409 + 145520886784 = 1515847^2 + 381472^2 .

It is a cyclic number.

It is not a de Polignac number, because 2443313014193 - 214 = 2443312997809 is a prime.

It is a super-3 number, since 3×24433130141933 (a number of 38 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (2443313014199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1221656507096 + 1221656507097.

It is an arithmetic number, because the mean of its divisors is an integer number (1221656507097).

Almost surely, 22443313014193 is an apocalyptic number.

It is an amenable number.

2443313014193 is a deficient number, since it is larger than the sum of its proper divisors (1).

2443313014193 is an equidigital number, since it uses as much as digits as its factorization.

2443313014193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 38.

The spelling of 2443313014193 in words is "two trillion, four hundred forty-three billion, three hundred thirteen million, fourteen thousand, one hundred ninety-three".