Base | Representation |
---|---|
bin | 1110010001010011110… |
… | …1110001100101101101 |
3 | 212102210221222000021222 |
4 | 3210110331301211231 |
5 | 13004044201432333 |
6 | 304343250033125 |
7 | 23466262021526 |
oct | 3442475614555 |
9 | 772727860258 |
10 | 245164874093 |
11 | 94a791a8627 |
12 | 3b6212787a5 |
13 | 1a171439449 |
14 | bc1a5cb84d |
15 | 659d5ce298 |
hex | 3914f7196d |
245164874093 has 2 divisors, whose sum is σ = 245164874094. Its totient is φ = 245164874092.
The previous prime is 245164874081. The next prime is 245164874231. The reversal of 245164874093 is 390478461542.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 238844306089 + 6320568004 = 488717^2 + 79502^2 .
It is a cyclic number.
It is not a de Polignac number, because 245164874093 - 210 = 245164873069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (245164871093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122582437046 + 122582437047.
It is an arithmetic number, because the mean of its divisors is an integer number (122582437047).
It is a 1-persistent number, because it is pandigital, but 2⋅245164874093 = 490329748186 is not.
Almost surely, 2245164874093 is an apocalyptic number.
It is an amenable number.
245164874093 is a deficient number, since it is larger than the sum of its proper divisors (1).
245164874093 is an equidigital number, since it uses as much as digits as its factorization.
245164874093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5806080, while the sum is 53.
The spelling of 245164874093 in words is "two hundred forty-five billion, one hundred sixty-four million, eight hundred seventy-four thousand, ninety-three".
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