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245574122116133 is a prime number
BaseRepresentation
bin110111110101100100101110…
…010100001001010000100101
31012012111122201210201112201002
4313311210232110021100211
5224141441300230204013
62230143105543443045
7102504100450533116
oct6765445624112045
91165448653645632
10245574122116133
117127a444915298
1223661ab0756485
13a7047041bc885
14448dbcad4220d
151d5ce2e569358
hexdf592e509425

245574122116133 has 2 divisors, whose sum is σ = 245574122116134. Its totient is φ = 245574122116132.

The previous prime is 245574122116121. The next prime is 245574122116199. The reversal of 245574122116133 is 331611221475542.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 146775333017569 + 98798789098564 = 12115087^2 + 9939758^2 .

It is a cyclic number.

It is not a de Polignac number, because 245574122116133 - 28 = 245574122115877 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (245574122116033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122787061058066 + 122787061058067.

It is an arithmetic number, because the mean of its divisors is an integer number (122787061058067).

Almost surely, 2245574122116133 is an apocalyptic number.

It is an amenable number.

245574122116133 is a deficient number, since it is larger than the sum of its proper divisors (1).

245574122116133 is an equidigital number, since it uses as much as digits as its factorization.

245574122116133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1209600, while the sum is 47.

The spelling of 245574122116133 in words is "two hundred forty-five trillion, five hundred seventy-four billion, one hundred twenty-two million, one hundred sixteen thousand, one hundred thirty-three".