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24714061133 is a prime number
BaseRepresentation
bin10111000001000100…
…101010010101001101
32100210100212101102112
4113001010222111031
5401103244424013
615204204033405
71533303024236
oct270104522515
970710771375
1024714061133
11a532496a13
124958832865
13243b21c918
1412a63d408d
15999a3eba8
hex5c112a54d

24714061133 has 2 divisors, whose sum is σ = 24714061134. Its totient is φ = 24714061132.

The previous prime is 24714061111. The next prime is 24714061147. The reversal of 24714061133 is 33116041742.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21478954249 + 3235106884 = 146557^2 + 56878^2 .

It is a cyclic number.

It is not a de Polignac number, because 24714061133 - 210 = 24714060109 is a prime.

It is a super-2 number, since 2×247140611332 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 24714061133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (24714061103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12357030566 + 12357030567.

It is an arithmetic number, because the mean of its divisors is an integer number (12357030567).

Almost surely, 224714061133 is an apocalyptic number.

It is an amenable number.

24714061133 is a deficient number, since it is larger than the sum of its proper divisors (1).

24714061133 is an equidigital number, since it uses as much as digits as its factorization.

24714061133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 32.

It can be divided in two parts, 2471 and 4061133, that added together give a palindrome (4063604).

The spelling of 24714061133 in words is "twenty-four billion, seven hundred fourteen million, sixty-one thousand, one hundred thirty-three".