Base | Representation |
---|---|
bin | 100100010000001101101… |
… | …100101000010000000101 |
3 | 22211011111201212020020022 |
4 | 210100031230220100011 |
5 | 311304201033202233 |
6 | 5144254205144525 |
7 | 344664001460102 |
oct | 44201554502005 |
9 | 8734451766208 |
10 | 2491310834693 |
11 | 88061702182a |
12 | 3429bab5b145 |
13 | 150c114543c5 |
14 | 88819a91aa9 |
15 | 44c10d83398 |
hex | 2440db28405 |
2491310834693 has 2 divisors, whose sum is σ = 2491310834694. Its totient is φ = 2491310834692.
The previous prime is 2491310834659. The next prime is 2491310834723. The reversal of 2491310834693 is 3964380131942.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2396112051844 + 95198782849 = 1547938^2 + 308543^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2491310834693 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2491310834393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1245655417346 + 1245655417347.
It is an arithmetic number, because the mean of its divisors is an integer number (1245655417347).
Almost surely, 22491310834693 is an apocalyptic number.
It is an amenable number.
2491310834693 is a deficient number, since it is larger than the sum of its proper divisors (1).
2491310834693 is an equidigital number, since it uses as much as digits as its factorization.
2491310834693 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3359232, while the sum is 53.
The spelling of 2491310834693 in words is "two trillion, four hundred ninety-one billion, three hundred ten million, eight hundred thirty-four thousand, six hundred ninety-three".
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