Base | Representation |
---|---|
bin | 1011010111101000100111… |
… | …00010100101110111001111 |
3 | 10021112002210211211212120022 |
4 | 11223310103202211313033 |
5 | 11234110212102340403 |
6 | 125101241550012355 |
7 | 5160200216401001 |
oct | 553642342456717 |
9 | 107462724755508 |
10 | 25001332465103 |
11 | 7a6a007436325 |
12 | 29795137a70bb |
13 | 10c480043bc97 |
14 | 6260dc976371 |
15 | 2d551e55bd38 |
hex | 16bd138a5dcf |
25001332465103 has 2 divisors, whose sum is σ = 25001332465104. Its totient is φ = 25001332465102.
The previous prime is 25001332465097. The next prime is 25001332465111. The reversal of 25001332465103 is 30156423310052.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 25001332465103 - 220 = 25001331416527 is a prime.
It is a super-2 number, since 2×250013324651032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25001332065103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12500666232551 + 12500666232552.
It is an arithmetic number, because the mean of its divisors is an integer number (12500666232552).
Almost surely, 225001332465103 is an apocalyptic number.
25001332465103 is a deficient number, since it is larger than the sum of its proper divisors (1).
25001332465103 is an equidigital number, since it uses as much as digits as its factorization.
25001332465103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 25001332465103 its reverse (30156423310052), we get a palindrome (55157755775155).
The spelling of 25001332465103 in words is "twenty-five trillion, one billion, three hundred thirty-two million, four hundred sixty-five thousand, one hundred three".
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