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25001375389 is a prime number
BaseRepresentation
bin10111010010001100…
…101011011010011101
32101112101111110111021
4113102030223122131
5402200323003024
615252510124141
71543362120154
oct272214533235
971471443437
1025001375389
11a66a696411
124a18ab0651
1324858c8563
1412d262459b
159b4d94de4
hex5d232b69d

25001375389 has 2 divisors, whose sum is σ = 25001375390. Its totient is φ = 25001375388.

The previous prime is 25001375387. The next prime is 25001375407. The reversal of 25001375389 is 98357310052.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21751235289 + 3250140100 = 147483^2 + 57010^2 .

It is a cyclic number.

It is not a de Polignac number, because 25001375389 - 21 = 25001375387 is a prime.

Together with 25001375387, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25001375381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12500687694 + 12500687695.

It is an arithmetic number, because the mean of its divisors is an integer number (12500687695).

Almost surely, 225001375389 is an apocalyptic number.

It is an amenable number.

25001375389 is a deficient number, since it is larger than the sum of its proper divisors (1).

25001375389 is an equidigital number, since it uses as much as digits as its factorization.

25001375389 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 226800, while the sum is 43.

The spelling of 25001375389 in words is "twenty-five billion, one million, three hundred seventy-five thousand, three hundred eighty-nine".