250043412313381 has 2 divisors, whose sum is σ = 250043412313382. Its totient is φ = 250043412313380.

The previous prime is 250043412313363. The next prime is 250043412313399. The reversal of 250043412313381 is 183313214340052.

250043412313381 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (250043412313363) and next prime (250043412313399).

It can be written as a sum of positive squares in only one way, i.e., 157856357528100 + 92187054785281 = 12564090^2 + 9601409^2 .

It is a cyclic number.

It is not a de Polignac number, because 250043412313381 - 2¹⁷ = 250043412182309 is a prime.

It is a super-2 number, since 2×250043412313381² (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (250043412313301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125021706156690 + 125021706156691.

It is an arithmetic number, because the mean of its divisors is an integer number (125021706156691).

Almost surely, 2^{250043412313381} is an apocalyptic number.

It is an amenable number.

250043412313381 is a deficient number, since it is larger than the sum of its proper divisors (1).

250043412313381 is an equidigital number, since it uses as much as digits as its factorization.

250043412313381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 207360, while the sum is 40.

The spelling of 250043412313381 in words is "two hundred fifty trillion, forty-three billion, four hundred twelve million, three hundred thirteen thousand, three hundred eighty-one".