Base | Representation |
---|---|
bin | 1011010111101111001100… |
… | …10101111011110110110011 |
3 | 10021112102221022201120022102 |
4 | 11223313212111323312303 |
5 | 11234134432444434031 |
6 | 125103024525131015 |
7 | 5160353652546134 |
oct | 553674625736663 |
9 | 107472838646272 |
10 | 25004869139891 |
11 | 7a70561832453 |
12 | 297a1400b9a6b |
13 | 10c4c45079764 |
14 | 62635655dc8b |
15 | 2d5679cb07cb |
hex | 16bde657bdb3 |
25004869139891 has 2 divisors, whose sum is σ = 25004869139892. Its totient is φ = 25004869139890.
The previous prime is 25004869139869. The next prime is 25004869139893. The reversal of 25004869139891 is 19893196840052.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 25004869139891 - 234 = 24987689270707 is a prime.
It is a Sophie Germain prime.
Together with 25004869139893, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (25004869139893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12502434569945 + 12502434569946.
It is an arithmetic number, because the mean of its divisors is an integer number (12502434569946).
Almost surely, 225004869139891 is an apocalyptic number.
25004869139891 is a deficient number, since it is larger than the sum of its proper divisors (1).
25004869139891 is an equidigital number, since it uses as much as digits as its factorization.
25004869139891 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33592320, while the sum is 65.
The spelling of 25004869139891 in words is "twenty-five trillion, four billion, eight hundred sixty-nine million, one hundred thirty-nine thousand, eight hundred ninety-one".
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