Base | Representation |
---|---|
bin | 1011010111101111001100… |
… | …10101111011110110110101 |
3 | 10021112102221022201120022111 |
4 | 11223313212111323312311 |
5 | 11234134432444434033 |
6 | 125103024525131021 |
7 | 5160353652546136 |
oct | 553674625736665 |
9 | 107472838646274 |
10 | 25004869139893 |
11 | 7a70561832455 |
12 | 297a1400b9a71 |
13 | 10c4c45079766 |
14 | 62635655dc8d |
15 | 2d5679cb07cd |
hex | 16bde657bdb5 |
25004869139893 has 2 divisors, whose sum is σ = 25004869139894. Its totient is φ = 25004869139892.
The previous prime is 25004869139891. The next prime is 25004869139941. The reversal of 25004869139893 is 39893196840052.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14155638710404 + 10849230429489 = 3762398^2 + 3293817^2 .
It is a cyclic number.
It is not a de Polignac number, because 25004869139893 - 21 = 25004869139891 is a prime.
Together with 25004869139891, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25004869139891) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12502434569946 + 12502434569947.
It is an arithmetic number, because the mean of its divisors is an integer number (12502434569947).
Almost surely, 225004869139893 is an apocalyptic number.
It is an amenable number.
25004869139893 is a deficient number, since it is larger than the sum of its proper divisors (1).
25004869139893 is an equidigital number, since it uses as much as digits as its factorization.
25004869139893 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100776960, while the sum is 67.
The spelling of 25004869139893 in words is "twenty-five trillion, four billion, eight hundred sixty-nine million, one hundred thirty-nine thousand, eight hundred ninety-three".
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