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25050252755573 is a prime number
BaseRepresentation
bin1011011001000011101110…
…11010101100001001110101
310021200210002012000010011022
411230201313122230021311
511240410404201134243
6125135532141350525
75163551421116363
oct554416732541165
9107623065003138
1025050252755573
117a88830692651
122986aa6b68445
1310c92c85b3716
1462861db2a633
152d6934227b68
hex16c8776ac275

25050252755573 has 2 divisors, whose sum is σ = 25050252755574. Its totient is φ = 25050252755572.

The previous prime is 25050252755537. The next prime is 25050252755587. The reversal of 25050252755573 is 37555725205052.

Together with previous prime (25050252755537) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21242162002084 + 3808090753489 = 4608922^2 + 1951433^2 .

It is a cyclic number.

It is not a de Polignac number, because 25050252755573 - 232 = 25045957788277 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25050252755533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12525126377786 + 12525126377787.

It is an arithmetic number, because the mean of its divisors is an integer number (12525126377787).

Almost surely, 225050252755573 is an apocalyptic number.

It is an amenable number.

25050252755573 is a deficient number, since it is larger than the sum of its proper divisors (1).

25050252755573 is an equidigital number, since it uses as much as digits as its factorization.

25050252755573 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18375000, while the sum is 53.

The spelling of 25050252755573 in words is "twenty-five trillion, fifty billion, two hundred fifty-two million, seven hundred fifty-five thousand, five hundred seventy-three".