Base | Representation |
---|---|
bin | 10111010110010000… |
… | …001011010000101011 |
3 | 2101201010111112021012 |
4 | 113112100023100223 |
5 | 402320231314011 |
6 | 15303340134135 |
7 | 1545146252015 |
oct | 272620132053 |
9 | 71633445235 |
10 | 25069401131 |
11 | a6a5029135 |
12 | 4a3783734b |
13 | 2496a25588 |
14 | 12db6911b5 |
15 | 9bad30a8b |
hex | 5d640b42b |
25069401131 has 2 divisors, whose sum is σ = 25069401132. Its totient is φ = 25069401130.
The previous prime is 25069401107. The next prime is 25069401167. The reversal of 25069401131 is 13110496052.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-25069401131 is a prime.
It is a super-3 number, since 3×250694011313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (25069401631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12534700565 + 12534700566.
It is an arithmetic number, because the mean of its divisors is an integer number (12534700566).
Almost surely, 225069401131 is an apocalyptic number.
25069401131 is a deficient number, since it is larger than the sum of its proper divisors (1).
25069401131 is an equidigital number, since it uses as much as digits as its factorization.
25069401131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 32.
Adding to 25069401131 its reverse (13110496052), we get a palindrome (38179897183).
The spelling of 25069401131 in words is "twenty-five billion, sixty-nine million, four hundred one thousand, one hundred thirty-one".
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