2510130050053 has 2 divisors, whose sum is σ = 2510130050054. Its totient is φ = 2510130050052.

The previous prime is 2510130050033. The next prime is 2510130050089. The reversal of 2510130050053 is 3500500310152.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1342221882849 + 1167908167204 = 1158543^2 + 1080698^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2510130050053 is a prime.

It is a super-3 number, since 3×2510130050053³ (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2510130050033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1255065025026 + 1255065025027.

It is an arithmetic number, because the mean of its divisors is an integer number (1255065025027).

Almost surely, 2^{2510130050053} is an apocalyptic number.

It is an amenable number.

2510130050053 is a deficient number, since it is larger than the sum of its proper divisors (1).

2510130050053 is an equidigital number, since it uses as much as digits as its factorization.

2510130050053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2250, while the sum is 25.

The spelling of 2510130050053 in words is "two trillion, five hundred ten billion, one hundred thirty million, fifty thousand, fifty-three".