Base | Representation |
---|---|
bin | 10111011000001100… |
… | …101010010011010010 |
3 | 2101210101220110022210 |
4 | 113120030222103102 |
5 | 402402110043010 |
6 | 15310503412550 |
7 | 1546023524655 |
oct | 273014522322 |
9 | 71711813283 |
10 | 25102034130 |
11 | a711497858 |
12 | 4a46754156 |
13 | 24a070cb44 |
14 | 1301b4789c |
15 | 9bdb29b20 |
hex | 5d832a4d2 |
25102034130 has 32 divisors (see below), whose sum is σ = 60249334464. Its totient is φ = 6693381056.
The previous prime is 25102034117. The next prime is 25102034137. The reversal of 25102034130 is 3143020152.
It is a super-2 number, since 2×251020341302 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 25102034097 and 25102034106.
It is not an unprimeable number, because it can be changed into a prime (25102034137) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 578989 + ... + 620831.
It is an arithmetic number, because the mean of its divisors is an integer number (1882791702).
Almost surely, 225102034130 is an apocalyptic number.
25102034130 is an abundant number, since it is smaller than the sum of its proper divisors (35147300334).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
25102034130 is a wasteful number, since it uses less digits than its factorization.
25102034130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61850.
The product of its (nonzero) digits is 720, while the sum is 21.
Adding to 25102034130 its reverse (3143020152), we get a palindrome (28245054282).
The spelling of 25102034130 in words is "twenty-five billion, one hundred two million, thirty-four thousand, one hundred thirty".
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