Base | Representation |
---|---|
bin | 10111011001010110… |
… | …010100011101101100 |
3 | 2101211202020110120201 |
4 | 113121112110131230 |
5 | 402422030441330 |
6 | 15312433323244 |
7 | 1546346616022 |
oct | 273126243554 |
9 | 71752213521 |
10 | 25121343340 |
11 | a721386085 |
12 | 4a51106524 |
13 | 24a4710a02 |
14 | 1304532712 |
15 | 9c0690eca |
hex | 5d959476c |
25121343340 has 24 divisors (see below), whose sum is σ = 52770261600. Its totient is φ = 10045596288.
The previous prime is 25121343329. The next prime is 25121343389. The reversal of 25121343340 is 4334312152.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 25121343299 and 25121343308.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 113112 + ... + 251071.
It is an arithmetic number, because the mean of its divisors is an integer number (2198760900).
Almost surely, 225121343340 is an apocalyptic number.
25121343340 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
25121343340 is an abundant number, since it is smaller than the sum of its proper divisors (27648918260).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
25121343340 is a wasteful number, since it uses less digits than its factorization.
25121343340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 367641 (or 367639 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 25121343340 its reverse (4334312152), we get a palindrome (29455655492).
The spelling of 25121343340 in words is "twenty-five billion, one hundred twenty-one million, three hundred forty-three thousand, three hundred forty".
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