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25130109581 is a prime number
BaseRepresentation
bin10111011001110111…
…110000101010001101
32101212100201211121022
4113121313300222031
5402431302001311
615313345243525
71546514256413
oct273167605215
971770654538
1025130109581
11a726323305
124a540335a5
1324a648cb35
1413057752b3
159c13235db
hex5d9df0a8d

25130109581 has 2 divisors, whose sum is σ = 25130109582. Its totient is φ = 25130109580.

The previous prime is 25130109551. The next prime is 25130109611. The reversal of 25130109581 is 18590103152.

It is a balanced prime because it is at equal distance from previous prime (25130109551) and next prime (25130109611).

It can be written as a sum of positive squares in only one way, i.e., 24387819556 + 742290025 = 156166^2 + 27245^2 .

It is a cyclic number.

It is not a de Polignac number, because 25130109581 - 218 = 25129847437 is a prime.

It is a super-2 number, since 2×251301095812 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25130109551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12565054790 + 12565054791.

It is an arithmetic number, because the mean of its divisors is an integer number (12565054791).

Almost surely, 225130109581 is an apocalyptic number.

It is an amenable number.

25130109581 is a deficient number, since it is larger than the sum of its proper divisors (1).

25130109581 is an equidigital number, since it uses as much as digits as its factorization.

25130109581 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 35.

The spelling of 25130109581 in words is "twenty-five billion, one hundred thirty million, one hundred nine thousand, five hundred eighty-one".