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251319985378589 is a prime number
BaseRepresentation
bin111001001001001011111110…
…011101000001010100011101
31012221211221210220011012101102
4321021023332131001110131
5230420111312224103324
62250302450222322445
7103636161344446241
oct7111137635012435
91187757726135342
10251319985378589
1173095230936336
122422b5b6729425
13aa304b043499a
14460bd48b74421
151e0c622452dae
hexe492fe74151d

251319985378589 has 2 divisors, whose sum is σ = 251319985378590. Its totient is φ = 251319985378588.

The previous prime is 251319985378459. The next prime is 251319985378591. The reversal of 251319985378589 is 985873589913152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 246741421080025 + 4578564298564 = 15708005^2 + 2139758^2 .

It is a cyclic number.

It is not a de Polignac number, because 251319985378589 - 28 = 251319985378333 is a prime.

It is a Sophie Germain prime.

Together with 251319985378591, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (251319985308589) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125659992689294 + 125659992689295.

It is an arithmetic number, because the mean of its divisors is an integer number (125659992689295).

Almost surely, 2251319985378589 is an apocalyptic number.

It is an amenable number.

251319985378589 is a deficient number, since it is larger than the sum of its proper divisors (1).

251319985378589 is an equidigital number, since it uses as much as digits as its factorization.

251319985378589 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5878656000, while the sum is 83.

The spelling of 251319985378589 in words is "two hundred fifty-one trillion, three hundred nineteen billion, nine hundred eighty-five million, three hundred seventy-eight thousand, five hundred eighty-nine".