Base | Representation |
---|---|
bin | 10111011010011110… |
… | …110110001110111111 |
3 | 2101220002000102002110 |
4 | 113122132312032333 |
5 | 402441412343111 |
6 | 15314353025103 |
7 | 1550000333430 |
oct | 273236661677 |
9 | 71802012073 |
10 | 25140356031 |
11 | a73109164a |
12 | 4a57555193 |
13 | 24a863991b |
14 | 1306c81487 |
15 | 9c21995a6 |
hex | 5da7b63bf |
25140356031 has 32 divisors (see below), whose sum is σ = 38578595328. Its totient is φ = 14265216000.
The previous prime is 25140355969. The next prime is 25140356083. The reversal of 25140356031 is 13065304152.
It is not a de Polignac number, because 25140356031 - 210 = 25140355007 is a prime.
It is a super-3 number, since 3×251403560313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 25140356031.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25140356231) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1769251 + ... + 1783403.
It is an arithmetic number, because the mean of its divisors is an integer number (1205581104).
Almost surely, 225140356031 is an apocalyptic number.
25140356031 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
25140356031 is a deficient number, since it is larger than the sum of its proper divisors (13438239297).
25140356031 is a wasteful number, since it uses less digits than its factorization.
25140356031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14751.
The product of its (nonzero) digits is 10800, while the sum is 30.
The spelling of 25140356031 in words is "twenty-five billion, one hundred forty million, three hundred fifty-six thousand, thirty-one".
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