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2514361125701 is a prime number
BaseRepresentation
bin100100100101101011100…
…110100000101101000101
322220101000011001100010002
4210211223212200231011
5312143402422010301
65203025341011045
7346441132635515
oct44455346405505
98811004040102
102514361125701
1188a375340607
12347372553a85
13153145a71259
14899a5111845
154560e7c916b
hex2496b9a0b45

2514361125701 has 2 divisors, whose sum is σ = 2514361125702. Its totient is φ = 2514361125700.

The previous prime is 2514361125673. The next prime is 2514361125713. The reversal of 2514361125701 is 1075211634152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2277775192900 + 236585932801 = 1509230^2 + 486401^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2514361125701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2514361125751) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1257180562850 + 1257180562851.

It is an arithmetic number, because the mean of its divisors is an integer number (1257180562851).

Almost surely, 22514361125701 is an apocalyptic number.

It is an amenable number.

2514361125701 is a deficient number, since it is larger than the sum of its proper divisors (1).

2514361125701 is an equidigital number, since it uses as much as digits as its factorization.

2514361125701 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 38.

Adding to 2514361125701 its reverse (1075211634152), we get a palindrome (3589572759853).

The spelling of 2514361125701 in words is "two trillion, five hundred fourteen billion, three hundred sixty-one million, one hundred twenty-five thousand, seven hundred one".