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2517125981 is a prime number
BaseRepresentation
bin1001011000001000…
…0100101101011101
320111102102020201012
42112002010231131
520123341012411
61053434425005
7116243134466
oct22602045535
96442366635
102517125981
111081941007
125a2b92165
13311647676
1419c42bd6d
15eaeb018b
hex96084b5d

2517125981 has 2 divisors, whose sum is σ = 2517125982. Its totient is φ = 2517125980.

The previous prime is 2517125969. The next prime is 2517125993. The reversal of 2517125981 is 1895217152.

It is a balanced prime because it is at equal distance from previous prime (2517125969) and next prime (2517125993).

It can be written as a sum of positive squares in only one way, i.e., 2505903481 + 11222500 = 50059^2 + 3350^2 .

It is a cyclic number.

It is not a de Polignac number, because 2517125981 - 26 = 2517125917 is a prime.

It is a super-2 number, since 2×25171259812 = 12671846408450424722, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2517115981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1258562990 + 1258562991.

It is an arithmetic number, because the mean of its divisors is an integer number (1258562991).

Almost surely, 22517125981 is an apocalyptic number.

It is an amenable number.

2517125981 is a deficient number, since it is larger than the sum of its proper divisors (1).

2517125981 is an equidigital number, since it uses as much as digits as its factorization.

2517125981 is an evil number, because the sum of its binary digits is even.

The product of its digits is 50400, while the sum is 41.

The square root of 2517125981 is about 50170.9675111015. The cubic root of 2517125981 is about 1360.3008959732.

The spelling of 2517125981 in words is "two billion, five hundred seventeen million, one hundred twenty-five thousand, nine hundred eighty-one".