Base | Representation |
---|---|
bin | 100100101010111101101… |
… | …111010010101011001101 |
3 | 22220220122111210122021022 |
4 | 210222331233102223031 |
5 | 312242012214022131 |
6 | 5205404313043525 |
7 | 350031536434541 |
oct | 44527557225315 |
9 | 8826574718238 |
10 | 2520034126541 |
11 | 891816627058 |
12 | 3484963b65a5 |
13 | 15383b178099 |
14 | 89d8271da21 |
15 | 4584286d37b |
hex | 24abdbd2acd |
2520034126541 has 2 divisors, whose sum is σ = 2520034126542. Its totient is φ = 2520034126540.
The previous prime is 2520034126523. The next prime is 2520034126543. The reversal of 2520034126541 is 1456214300252.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1546317120100 + 973717006441 = 1243510^2 + 986771^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2520034126541 is a prime.
Together with 2520034126543, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2520034126543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1260017063270 + 1260017063271.
It is an arithmetic number, because the mean of its divisors is an integer number (1260017063271).
Almost surely, 22520034126541 is an apocalyptic number.
It is an amenable number.
2520034126541 is a deficient number, since it is larger than the sum of its proper divisors (1).
2520034126541 is an equidigital number, since it uses as much as digits as its factorization.
2520034126541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 2520034126541 its reverse (1456214300252), we get a palindrome (3976248426793).
The spelling of 2520034126541 in words is "two trillion, five hundred twenty billion, thirty-four million, one hundred twenty-six thousand, five hundred forty-one".
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