Base | Representation |
---|---|
bin | 111001010011011001000101… |
… | …010010001111001001000111 |
3 | 1020001022222220110122220220002 |
4 | 321103121011102033021013 |
5 | 231013104011332400312 |
6 | 2252000544314031515 |
7 | 104040635412346451 |
oct | 7123310522171107 |
9 | 1201288813586802 |
10 | 252021253403207 |
11 | 73335682402662 |
12 | 243234a7a1859b |
13 | aa8166b4c2742 |
14 | 4633c726352d1 |
15 | 1e209b79d14c2 |
hex | e5364548f247 |
252021253403207 has 2 divisors, whose sum is σ = 252021253403208. Its totient is φ = 252021253403206.
The previous prime is 252021253403173. The next prime is 252021253403221. The reversal of 252021253403207 is 702304352120252.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 252021253403207 - 220 = 252021252354631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (252021253403407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126010626701603 + 126010626701604.
It is an arithmetic number, because the mean of its divisors is an integer number (126010626701604).
Almost surely, 2252021253403207 is an apocalyptic number.
252021253403207 is a deficient number, since it is larger than the sum of its proper divisors (1).
252021253403207 is an equidigital number, since it uses as much as digits as its factorization.
252021253403207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 201600, while the sum is 38.
The spelling of 252021253403207 in words is "two hundred fifty-two trillion, twenty-one billion, two hundred fifty-three million, four hundred three thousand, two hundred seven".
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