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252045124343 is a prime number
BaseRepresentation
bin1110101010111100001…
…1110110001011110111
3220002120110100221022022
43222233003312023313
513112142022434333
6311442105423355
724131625131255
oct3525703661367
9802513327268
10252045124343
11979899a1461
1240a2149ab5b
131a9c99a533c
14c2b02955d5
156852641c98
hex3aaf0f62f7

252045124343 has 2 divisors, whose sum is σ = 252045124344. Its totient is φ = 252045124342.

The previous prime is 252045124327. The next prime is 252045124349. The reversal of 252045124343 is 343421540252.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 252045124343 - 24 = 252045124327 is a prime.

It is a super-4 number, since 4×2520451243434 (a number of 47 digits) contains 4444 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (252045124349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126022562171 + 126022562172.

It is an arithmetic number, because the mean of its divisors is an integer number (126022562172).

Almost surely, 2252045124343 is an apocalyptic number.

252045124343 is a deficient number, since it is larger than the sum of its proper divisors (1).

252045124343 is an equidigital number, since it uses as much as digits as its factorization.

252045124343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 115200, while the sum is 35.

Adding to 252045124343 its reverse (343421540252), we get a palindrome (595466664595).

The spelling of 252045124343 in words is "two hundred fifty-two billion, forty-five million, one hundred twenty-four thousand, three hundred forty-three".