Base | Representation |
---|---|
bin | 1110101010111100001… |
… | …1110110001011110111 |
3 | 220002120110100221022022 |
4 | 3222233003312023313 |
5 | 13112142022434333 |
6 | 311442105423355 |
7 | 24131625131255 |
oct | 3525703661367 |
9 | 802513327268 |
10 | 252045124343 |
11 | 979899a1461 |
12 | 40a2149ab5b |
13 | 1a9c99a533c |
14 | c2b02955d5 |
15 | 6852641c98 |
hex | 3aaf0f62f7 |
252045124343 has 2 divisors, whose sum is σ = 252045124344. Its totient is φ = 252045124342.
The previous prime is 252045124327. The next prime is 252045124349. The reversal of 252045124343 is 343421540252.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 252045124343 - 24 = 252045124327 is a prime.
It is a super-4 number, since 4×2520451243434 (a number of 47 digits) contains 4444 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (252045124349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126022562171 + 126022562172.
It is an arithmetic number, because the mean of its divisors is an integer number (126022562172).
Almost surely, 2252045124343 is an apocalyptic number.
252045124343 is a deficient number, since it is larger than the sum of its proper divisors (1).
252045124343 is an equidigital number, since it uses as much as digits as its factorization.
252045124343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 115200, while the sum is 35.
Adding to 252045124343 its reverse (343421540252), we get a palindrome (595466664595).
The spelling of 252045124343 in words is "two hundred fifty-two billion, forty-five million, one hundred twenty-four thousand, three hundred forty-three".
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