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25214520500053 is a prime number
BaseRepresentation
bin1011011101110101101101…
…00010011001111101010101
310022021111002021202010222121
411232322312202121331111
511301103314222000203
6125343220225255541
75211455215654333
oct556726642317525
9108244067663877
1025214520500053
118041466532365
1229b28aba945b1
13110b946a88021
1463256436cb53
152dad4a6c70bd
hex16eeb6899f55

25214520500053 has 2 divisors, whose sum is σ = 25214520500054. Its totient is φ = 25214520500052.

The previous prime is 25214520500027. The next prime is 25214520500077. The reversal of 25214520500053 is 35000502541252.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23616275876964 + 1598244623089 = 4859658^2 + 1264217^2 .

It is a cyclic number.

It is not a de Polignac number, because 25214520500053 - 25 = 25214520500021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25214520499991 and 25214520500018.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25214520500083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12607260250026 + 12607260250027.

It is an arithmetic number, because the mean of its divisors is an integer number (12607260250027).

Almost surely, 225214520500053 is an apocalyptic number.

It is an amenable number.

25214520500053 is a deficient number, since it is larger than the sum of its proper divisors (1).

25214520500053 is an equidigital number, since it uses as much as digits as its factorization.

25214520500053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60000, while the sum is 34.

The spelling of 25214520500053 in words is "twenty-five trillion, two hundred fourteen billion, five hundred twenty million, five hundred thousand, fifty-three".