Search a number
-
+
2527967870413 is a prime number
BaseRepresentation
bin100100110010010110101…
…000000111110111001101
322221200010102112120211221
4210302112220013313031
5312404234233323123
65213155444443341
7350432254233256
oct44622650076715
98850112476757
102527967870413
11895117a60277
12349b2b3a9551
13154503a6079b
148a4d629bb2d
1545b5912c25d
hex24c96a07dcd

2527967870413 has 2 divisors, whose sum is σ = 2527967870414. Its totient is φ = 2527967870412.

The previous prime is 2527967870387. The next prime is 2527967870419. The reversal of 2527967870413 is 3140787697252.

2527967870413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1769001081444 + 758966788969 = 1330038^2 + 871187^2 .

It is a cyclic number.

It is not a de Polignac number, because 2527967870413 - 225 = 2527934315981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2527967870419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1263983935206 + 1263983935207.

It is an arithmetic number, because the mean of its divisors is an integer number (1263983935207).

It is a 1-persistent number, because it is pandigital, but 2⋅2527967870413 = 5055935740826 is not.

Almost surely, 22527967870413 is an apocalyptic number.

It is an amenable number.

2527967870413 is a deficient number, since it is larger than the sum of its proper divisors (1).

2527967870413 is an equidigital number, since it uses as much as digits as its factorization.

2527967870413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 35562240, while the sum is 61.

The spelling of 2527967870413 in words is "two trillion, five hundred twenty-seven billion, nine hundred sixty-seven million, eight hundred seventy thousand, four hundred thirteen".