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2530236613441 is a prime number
BaseRepresentation
bin100100110100011101110…
…110101100001101000001
322221212222112120200012111
4210310131312230031001
5312423411033112231
65214212531455321
7350542423232365
oct44643566541501
98855875520174
102530236613441
11896081672509
1234a463157541
131547a5ab0794
148a66d7112a5
1545c3d3c74b1
hex24d1ddac341

2530236613441 has 2 divisors, whose sum is σ = 2530236613442. Its totient is φ = 2530236613440.

The previous prime is 2530236613439. The next prime is 2530236613511. The reversal of 2530236613441 is 1443166320352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2525226097216 + 5010516225 = 1589096^2 + 70785^2 .

It is a cyclic number.

It is not a de Polignac number, because 2530236613441 - 21 = 2530236613439 is a prime.

Together with 2530236613439, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 2530236613394 and 2530236613403.

It is not a weakly prime, because it can be changed into another prime (2530236673441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265118306720 + 1265118306721.

It is an arithmetic number, because the mean of its divisors is an integer number (1265118306721).

Almost surely, 22530236613441 is an apocalyptic number.

It is an amenable number.

2530236613441 is a deficient number, since it is larger than the sum of its proper divisors (1).

2530236613441 is an equidigital number, since it uses as much as digits as its factorization.

2530236613441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 40.

The spelling of 2530236613441 in words is "two trillion, five hundred thirty billion, two hundred thirty-six million, six hundred thirteen thousand, four hundred forty-one".