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2530236613439 is a prime number
BaseRepresentation
bin100100110100011101110…
…110101100001100111111
322221212222112120200012102
4210310131312230030333
5312423411033112224
65214212531455315
7350542423232363
oct44643566541477
98855875520172
102530236613439
11896081672507
1234a46315753b
131547a5ab0792
148a66d7112a3
1545c3d3c74ae
hex24d1ddac33f

2530236613439 has 2 divisors, whose sum is σ = 2530236613440. Its totient is φ = 2530236613438.

The previous prime is 2530236613417. The next prime is 2530236613441. The reversal of 2530236613439 is 9343166320352.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2530236613439 - 216 = 2530236547903 is a prime.

Together with 2530236613441, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2530236613393 and 2530236613402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2530236613939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265118306719 + 1265118306720.

It is an arithmetic number, because the mean of its divisors is an integer number (1265118306720).

Almost surely, 22530236613439 is an apocalyptic number.

2530236613439 is a deficient number, since it is larger than the sum of its proper divisors (1).

2530236613439 is an equidigital number, since it uses as much as digits as its factorization.

2530236613439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2099520, while the sum is 47.

The spelling of 2530236613439 in words is "two trillion, five hundred thirty billion, two hundred thirty-six million, six hundred thirteen thousand, four hundred thirty-nine".