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253148503 is a prime number
BaseRepresentation
bin11110001011010…
…11110101010111
3122122100021110111
433011223311113
51004301223003
641041503451
76162504166
oct1705536527
9578307414
10253148503
1111a994243
1270941b87
13405a581a
14258993dd
1517356e6d
hexf16bd57

253148503 has 2 divisors, whose sum is σ = 253148504. Its totient is φ = 253148502.

The previous prime is 253148501. The next prime is 253148509. The reversal of 253148503 is 305841352.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 253148503 - 21 = 253148501 is a prime.

It is a super-2 number, since 2×2531485032 = 128168329142282018, which contains 22 as substring.

Together with 253148501, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (253148501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126574251 + 126574252.

It is an arithmetic number, because the mean of its divisors is an integer number (126574252).

Almost surely, 2253148503 is an apocalyptic number.

253148503 is a deficient number, since it is larger than the sum of its proper divisors (1).

253148503 is an equidigital number, since it uses as much as digits as its factorization.

253148503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

The square root of 253148503 is about 15910.6411875826. The cubic root of 253148503 is about 632.5940768375.

Adding to 253148503 its reverse (305841352), we get a palindrome (558989855).

The spelling of 253148503 in words is "two hundred fifty-three million, one hundred forty-eight thousand, five hundred three".