Base | Representation |
---|---|
bin | 1110101111000100011… |
… | …1010100001111000101 |
3 | 220012102200122121211121 |
4 | 3223301013110033011 |
5 | 13121424223030432 |
6 | 312144054233541 |
7 | 24201242542012 |
oct | 3536107241705 |
9 | 805380577747 |
10 | 253153330117 |
11 | 983a85008a6 |
12 | 410906558b1 |
13 | 1ab45469cbc |
14 | c37752c709 |
15 | 68b9a99197 |
hex | 3af11d43c5 |
253153330117 has 2 divisors, whose sum is σ = 253153330118. Its totient is φ = 253153330116.
The previous prime is 253153330109. The next prime is 253153330127. The reversal of 253153330117 is 711033351352.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 134132470081 + 119020860036 = 366241^2 + 344994^2 .
It is a cyclic number.
It is not a de Polignac number, because 253153330117 - 23 = 253153330109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (253153330127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126576665058 + 126576665059.
It is an arithmetic number, because the mean of its divisors is an integer number (126576665059).
Almost surely, 2253153330117 is an apocalyptic number.
It is an amenable number.
253153330117 is a deficient number, since it is larger than the sum of its proper divisors (1).
253153330117 is an equidigital number, since it uses as much as digits as its factorization.
253153330117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28350, while the sum is 34.
Adding to 253153330117 its reverse (711033351352), we get a palindrome (964186681469).
The spelling of 253153330117 in words is "two hundred fifty-three billion, one hundred fifty-three million, three hundred thirty thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •