Base | Representation |
---|---|
bin | 1011100000111011001101… |
… | …01011111110000001100111 |
3 | 10022122121210000101110200011 |
4 | 11300131212223332001213 |
5 | 11304322444040342244 |
6 | 125504034041031051 |
7 | 5222230646311606 |
oct | 560354653760147 |
9 | 108577700343604 |
10 | 25320555012199 |
11 | 8082429220787 |
12 | 2a0b362785487 |
13 | 11189448581c5 |
14 | 637742a23a3d |
15 | 2dd9a45b5434 |
hex | 170766afe067 |
25320555012199 has 2 divisors, whose sum is σ = 25320555012200. Its totient is φ = 25320555012198.
The previous prime is 25320555012197. The next prime is 25320555012227. The reversal of 25320555012199 is 99121055502352.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 25320555012199 - 21 = 25320555012197 is a prime.
It is a super-2 number, since 2×253205550121992 (a number of 28 digits) contains 22 as substring.
Together with 25320555012197, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25320555012197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12660277506099 + 12660277506100.
It is an arithmetic number, because the mean of its divisors is an integer number (12660277506100).
Almost surely, 225320555012199 is an apocalyptic number.
25320555012199 is a deficient number, since it is larger than the sum of its proper divisors (1).
25320555012199 is an equidigital number, since it uses as much as digits as its factorization.
25320555012199 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1215000, while the sum is 49.
The spelling of 25320555012199 in words is "twenty-five trillion, three hundred twenty billion, five hundred fifty-five million, twelve thousand, one hundred ninety-nine".
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