Base | Representation |
---|---|
bin | 111001100110101001000111… |
… | …100010101100011010011111 |
3 | 1020020000110111210102212110222 |
4 | 321212221013202230122133 |
5 | 231201242300121332012 |
6 | 2254452405230351555 |
7 | 104235336664155605 |
oct | 7146510742543237 |
9 | 1206013453385428 |
10 | 253344141199007 |
11 | 737a5713047571 |
12 | 244b796035b5bb |
13 | ab49333351601 |
14 | 467bcc9821875 |
15 | 1e450e0e50972 |
hex | e66a478ac69f |
253344141199007 has 2 divisors, whose sum is σ = 253344141199008. Its totient is φ = 253344141199006.
The previous prime is 253344141198991. The next prime is 253344141199031. The reversal of 253344141199007 is 700991141443352.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 253344141199007 - 24 = 253344141198991 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 253344141199007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (253344141399007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126672070599503 + 126672070599504.
It is an arithmetic number, because the mean of its divisors is an integer number (126672070599504).
Almost surely, 2253344141199007 is an apocalyptic number.
253344141199007 is a deficient number, since it is larger than the sum of its proper divisors (1).
253344141199007 is an equidigital number, since it uses as much as digits as its factorization.
253344141199007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3265920, while the sum is 53.
The spelling of 253344141199007 in words is "two hundred fifty-three trillion, three hundred forty-four billion, one hundred forty-one million, one hundred ninety-nine thousand, seven".
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