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253355515435133 is a prime number
BaseRepresentation
bin111001100110110011101101…
…011111111101100001111101
31020020001112212111001221011122
4321212303231133331201331
5231201434043422411013
62254501530024000325
7104236221566450066
oct7146635537754175
91206045774057148
10253355515435133
11737aa51a553511
12244b9bb56000a5
13ab4a426969747
14467c6882ab56d
151e455597b4a08
hexe66ced7fd87d

253355515435133 has 2 divisors, whose sum is σ = 253355515435134. Its totient is φ = 253355515435132.

The previous prime is 253355515435081. The next prime is 253355515435177. The reversal of 253355515435133 is 331534515553352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 219723611747929 + 33631903687204 = 14823077^2 + 5799302^2 .

It is a cyclic number.

It is not a de Polignac number, because 253355515435133 - 216 = 253355515369597 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (253355515438133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126677757717566 + 126677757717567.

It is an arithmetic number, because the mean of its divisors is an integer number (126677757717567).

Almost surely, 2253355515435133 is an apocalyptic number.

It is an amenable number.

253355515435133 is a deficient number, since it is larger than the sum of its proper divisors (1).

253355515435133 is an equidigital number, since it uses as much as digits as its factorization.

253355515435133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 30375000, while the sum is 53.

The spelling of 253355515435133 in words is "two hundred fifty-three trillion, three hundred fifty-five billion, five hundred fifteen million, four hundred thirty-five thousand, one hundred thirty-three".