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2534108306453 is a prime number
BaseRepresentation
bin100100111000000100101…
…000000001110000010101
322222020222100212001112222
4210320010220001300111
5313004323211301303
65220053035352125
7351040365126203
oct44700450016025
98866870761488
102534108306453
118977890907a9
1234b1638b2645
13154c71c5a1a9
148a9199c6073
1545db8255938
hex24e04a01c15

2534108306453 has 2 divisors, whose sum is σ = 2534108306454. Its totient is φ = 2534108306452.

The previous prime is 2534108306447. The next prime is 2534108306497. The reversal of 2534108306453 is 3546038014352.

It is an a-pointer prime, because the next prime (2534108306497) can be obtained adding 2534108306453 to its sum of digits (44).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2065707684049 + 468400622404 = 1437257^2 + 684398^2 .

It is a cyclic number.

It is not a de Polignac number, because 2534108306453 - 214 = 2534108290069 is a prime.

It is a super-2 number, since 2×25341083064532 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2534108306153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1267054153226 + 1267054153227.

It is an arithmetic number, because the mean of its divisors is an integer number (1267054153227).

Almost surely, 22534108306453 is an apocalyptic number.

It is an amenable number.

2534108306453 is a deficient number, since it is larger than the sum of its proper divisors (1).

2534108306453 is an equidigital number, since it uses as much as digits as its factorization.

2534108306453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1036800, while the sum is 44.

The spelling of 2534108306453 in words is "two trillion, five hundred thirty-four billion, one hundred eight million, three hundred six thousand, four hundred fifty-three".