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25341316054213 is a prime number
BaseRepresentation
bin1011100001100001111000…
…01001000011110011000101
310022201121100212221200022011
411300300330021003303011
511310143003402213323
6125521350114134221
75223564302254105
oct560607411036305
9108647325850264
1025341316054213
1180902122a1945
122a13397581371
13111a8a2ac5553
14638752013205
152de2bc06020d
hex170c3c243cc5

25341316054213 has 2 divisors, whose sum is σ = 25341316054214. Its totient is φ = 25341316054212.

The previous prime is 25341316054147. The next prime is 25341316054217. The reversal of 25341316054213 is 31245061314352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15014206783489 + 10327109270724 = 3874817^2 + 3213582^2 .

It is a cyclic number.

It is not a de Polignac number, because 25341316054213 - 225 = 25341282499781 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25341316054217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12670658027106 + 12670658027107.

It is an arithmetic number, because the mean of its divisors is an integer number (12670658027107).

Almost surely, 225341316054213 is an apocalyptic number.

It is an amenable number.

25341316054213 is a deficient number, since it is larger than the sum of its proper divisors (1).

25341316054213 is an equidigital number, since it uses as much as digits as its factorization.

25341316054213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 40.

Adding to 25341316054213 its reverse (31245061314352), we get a palindrome (56586377368565).

The spelling of 25341316054213 in words is "twenty-five trillion, three hundred forty-one billion, three hundred sixteen million, fifty-four thousand, two hundred thirteen".