25341316054147 has 2 divisors, whose sum is σ = 25341316054148. Its totient is φ = 25341316054146.

The previous prime is 25341316054081. The next prime is 25341316054213. The reversal of 25341316054147 is 74145061314352.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (25341316054081) and next prime (25341316054213).

It is a cyclic number.

It is not a de Polignac number, because 25341316054147 - 2¹⁵ = 25341316021379 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25341316054097 and 25341316054106.

It is not a weakly prime, because it can be changed into another prime (25341316054247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12670658027073 + 12670658027074.

It is an arithmetic number, because the mean of its divisors is an integer number (12670658027074).

Almost surely, 2^{25341316054147} is an apocalyptic number.

25341316054147 is a deficient number, since it is larger than the sum of its proper divisors (1).

25341316054147 is an equidigital number, since it uses as much as digits as its factorization.

25341316054147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1209600, while the sum is 46.

Adding to 25341316054147 its reverse (74145061314352), we get a palindrome (99486377368499).

The spelling of 25341316054147 in words is "twenty-five trillion, three hundred forty-one billion, three hundred sixteen million, fifty-four thousand, one hundred forty-seven".