Base | Representation |
---|---|
bin | 1110110000001011111… |
… | …1010010010100000111 |
3 | 220020012120221100112111 |
4 | 3230002333102110013 |
5 | 13123033010334413 |
6 | 312233530001451 |
7 | 24211543531633 |
oct | 3540277222407 |
9 | 806176840474 |
10 | 253453214983 |
11 | 98541806831 |
12 | 41154b76287 |
13 | 1ab92627577 |
14 | c3a52b1dc3 |
15 | 68d6083d3d |
hex | 3b02fd2507 |
253453214983 has 2 divisors, whose sum is σ = 253453214984. Its totient is φ = 253453214982.
The previous prime is 253453214939. The next prime is 253453215011. The reversal of 253453214983 is 389412354352.
It is a happy number.
253453214983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 253453214983 - 217 = 253453083911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (253453214923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126726607491 + 126726607492.
It is an arithmetic number, because the mean of its divisors is an integer number (126726607492).
Almost surely, 2253453214983 is an apocalyptic number.
253453214983 is a deficient number, since it is larger than the sum of its proper divisors (1).
253453214983 is an equidigital number, since it uses as much as digits as its factorization.
253453214983 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3110400, while the sum is 49.
The spelling of 253453214983 in words is "two hundred fifty-three billion, four hundred fifty-three million, two hundred fourteen thousand, nine hundred eighty-three".
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