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2535430413244 = 226128336717697
BaseRepresentation
bin100100111001010011011…
…011011101101110111100
322222101101111122001010011
4210321103123131232330
5313020030141210434
65220432144553004
7351115220632021
oct44712333355674
98871344561104
102535430413244
118982a7408143
1234b472622764
13155122b354c1
148aa0341d548
1545e44360e64
hex24e536ddbbc

2535430413244 has 24 divisors (see below), whose sum is σ = 4525676584688. Its totient is φ = 1242526832640.

The previous prime is 2535430413223. The next prime is 2535430413247. The reversal of 2535430413244 is 4423140345352.

It is a super-2 number, since 2×25354304132442 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2535430413197 and 2535430413206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2535430413247) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18289797 + ... + 18427900.

Almost surely, 22535430413244 is an apocalyptic number.

It is an amenable number.

2535430413244 is a deficient number, since it is larger than the sum of its proper divisors (1990246171444).

2535430413244 is a wasteful number, since it uses less digits than its factorization.

2535430413244 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36718045 (or 36718043 counting only the distinct ones).

The product of its (nonzero) digits is 691200, while the sum is 40.

Adding to 2535430413244 its reverse (4423140345352), we get a palindrome (6958570758596).

The spelling of 2535430413244 in words is "two trillion, five hundred thirty-five billion, four hundred thirty million, four hundred thirteen thousand, two hundred forty-four".

Divisors: 1 2 4 61 122 244 283 566 1132 17263 34526 69052 36717697 73435394 146870788 2239779517 4479559034 8959118068 10391108251 20782216502 41564433004 633857603311 1267715206622 2535430413244