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25382859249427 is a prime number
BaseRepresentation
bin1011100010101111010000…
…10011110001011100010011
310022212120121002210122122221
411301113220103301130103
511311333043431440202
6125552420301041511
75226564625506241
oct561275023613423
9108776532718587
1025382859249427
1180a68a0353329
122a1b450256297
1311217937b2074
1463a773529791
152e03ee275037
hex1715e84f1713

25382859249427 has 2 divisors, whose sum is σ = 25382859249428. Its totient is φ = 25382859249426.

The previous prime is 25382859249389. The next prime is 25382859249497. The reversal of 25382859249427 is 72494295828352.

It is a happy number.

It is an a-pointer prime, because the next prime (25382859249497) can be obtained adding 25382859249427 to its sum of digits (70).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25382859249427 is a prime.

It is a super-3 number, since 3×253828592494273 (a number of 41 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (25382859249497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12691429624713 + 12691429624714.

It is an arithmetic number, because the mean of its divisors is an integer number (12691429624714).

Almost surely, 225382859249427 is an apocalyptic number.

25382859249427 is a deficient number, since it is larger than the sum of its proper divisors (1).

25382859249427 is an equidigital number, since it uses as much as digits as its factorization.

25382859249427 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 696729600, while the sum is 70.

The spelling of 25382859249427 in words is "twenty-five trillion, three hundred eighty-two billion, eight hundred fifty-nine million, two hundred forty-nine thousand, four hundred twenty-seven".