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2538885103 is a prime number
BaseRepresentation
bin1001011101010100…
…0100111111101111
320112221100201121121
42113111010333233
520144423310403
61055533041411
7116626111246
oct22725047757
96487321547
102538885103
111093152a57
125aa326267
13315cc56a1
141a129395d
15ecd5c3bd
hex97544fef

2538885103 has 2 divisors, whose sum is σ = 2538885104. Its totient is φ = 2538885102.

The previous prime is 2538885101. The next prime is 2538885131. The reversal of 2538885103 is 3015888352.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2538885103 - 21 = 2538885101 is a prime.

It is a super-4 number, since 4×25388851034 (a number of 39 digits) contains 4444 as substring.

Together with 2538885101, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 2538885103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2538885101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1269442551 + 1269442552.

It is an arithmetic number, because the mean of its divisors is an integer number (1269442552).

Almost surely, 22538885103 is an apocalyptic number.

2538885103 is a deficient number, since it is larger than the sum of its proper divisors (1).

2538885103 is an equidigital number, since it uses as much as digits as its factorization.

2538885103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 230400, while the sum is 43.

The square root of 2538885103 is about 50387.3506249336. The cubic root of 2538885103 is about 1364.2093312180.

The spelling of 2538885103 in words is "two billion, five hundred thirty-eight million, eight hundred eighty-five thousand, one hundred three".