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25400279531831 is a prime number
BaseRepresentation
bin1011100011001111101101…
…01000111000000100110111
310022221020120011010200122112
411301213312220320010313
511312124233030004311
6130004421034121235
75231052414455501
oct561476650700467
9108836504120575
1025400279531831
11810321a680336
122a228b228021b
13112330b898889
1463b546d6cd71
152e0abd7ba28b
hex1719f6a38137

25400279531831 has 2 divisors, whose sum is σ = 25400279531832. Its totient is φ = 25400279531830.

The previous prime is 25400279531791. The next prime is 25400279531833. The reversal of 25400279531831 is 13813597200452.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 25400279531831 - 226 = 25400212422967 is a prime.

It is a super-2 number, since 2×254002795318312 (a number of 28 digits) contains 22 as substring.

Together with 25400279531833, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 25400279531831.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25400279531833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12700139765915 + 12700139765916.

It is an arithmetic number, because the mean of its divisors is an integer number (12700139765916).

Almost surely, 225400279531831 is an apocalyptic number.

25400279531831 is a deficient number, since it is larger than the sum of its proper divisors (1).

25400279531831 is an equidigital number, since it uses as much as digits as its factorization.

25400279531831 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1814400, while the sum is 50.

The spelling of 25400279531831 in words is "twenty-five trillion, four hundred billion, two hundred seventy-nine million, five hundred thirty-one thousand, eight hundred thirty-one".