Base | Representation |
---|---|
bin | 100100111110100110001… |
… | …110010001101101010111 |
3 | 22222221001122010010111001 |
4 | 210332212032101231113 |
5 | 313113200243313333 |
6 | 5223212153124131 |
7 | 351406120201204 |
oct | 44764616215527 |
9 | 8887048103431 |
10 | 2541114432343 |
11 | 89a753939893 |
12 | 35059a0b9647 |
13 | 15581a5c9506 |
14 | 8adc2298cab |
15 | 4617837eb7d |
hex | 24fa6391b57 |
2541114432343 has 2 divisors, whose sum is σ = 2541114432344. Its totient is φ = 2541114432342.
The previous prime is 2541114432341. The next prime is 2541114432433. The reversal of 2541114432343 is 3432344111452.
Together with next prime (2541114432433) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2541114432343 - 21 = 2541114432341 is a prime.
Together with 2541114432341, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2541114432341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1270557216171 + 1270557216172.
It is an arithmetic number, because the mean of its divisors is an integer number (1270557216172).
Almost surely, 22541114432343 is an apocalyptic number.
2541114432343 is a deficient number, since it is larger than the sum of its proper divisors (1).
2541114432343 is an equidigital number, since it uses as much as digits as its factorization.
2541114432343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 138240, while the sum is 37.
Adding to 2541114432343 its reverse (3432344111452), we get a palindrome (5973458543795).
The spelling of 2541114432343 in words is "two trillion, five hundred forty-one billion, one hundred fourteen million, four hundred thirty-two thousand, three hundred forty-three".
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