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25420689317 is a prime number
BaseRepresentation
bin10111101011001100…
…001110111110100101
32102121121111211001202
4113223030032332211
5404030144024232
615402245332245
71556643202562
oct275314167645
972547454052
1025420689317
11a865353151
124b15407085
13252173cbca
1413321b5869
159dbac1162
hex5eb30efa5

25420689317 has 2 divisors, whose sum is σ = 25420689318. Its totient is φ = 25420689316.

The previous prime is 25420689277. The next prime is 25420689341. The reversal of 25420689317 is 71398602452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19443234721 + 5977454596 = 139439^2 + 77314^2 .

It is a cyclic number.

It is not a de Polignac number, because 25420689317 - 226 = 25353580453 is a prime.

It is a super-2 number, since 2×254206893172 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25420689377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12710344658 + 12710344659.

It is an arithmetic number, because the mean of its divisors is an integer number (12710344659).

It is a 1-persistent number, because it is pandigital, but 2⋅25420689317 = 50841378634 is not.

Almost surely, 225420689317 is an apocalyptic number.

It is an amenable number.

25420689317 is a deficient number, since it is larger than the sum of its proper divisors (1).

25420689317 is an equidigital number, since it uses as much as digits as its factorization.

25420689317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 725760, while the sum is 47.

The spelling of 25420689317 in words is "twenty-five billion, four hundred twenty million, six hundred eighty-nine thousand, three hundred seventeen".