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2542131535 = 54794711423
BaseRepresentation
bin1001011110000101…
…1101100101001111
320120011110122212211
42113201131211033
520201241202120
61100130411251
7116665522126
oct22741354517
96504418784
102542131535
111094a70059
125ab430b27
13316891258
141a189aabd
15ed29e25a
hex9785d94f

2542131535 has 16 divisors (see below), whose sum is σ = 3119026176. Its totient is φ = 1988159008.

The previous prime is 2542131517. The next prime is 2542131541. The reversal of 2542131535 is 5351312452.

It is a cyclic number.

It is not a de Polignac number, because 2542131535 - 223 = 2533742927 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2542131497 and 2542131506.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 216834 + ... + 228256.

It is an arithmetic number, because the mean of its divisors is an integer number (194939136).

Almost surely, 22542131535 is an apocalyptic number.

2542131535 is a deficient number, since it is larger than the sum of its proper divisors (576894641).

2542131535 is a wasteful number, since it uses less digits than its factorization.

2542131535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12422.

The product of its digits is 18000, while the sum is 31.

The square root of 2542131535 is about 50419.5550853040. Note that the first 3 decimals coincide. The cubic root of 2542131535 is about 1364.7905478155.

Adding to 2542131535 its reverse (5351312452), we get a palindrome (7893443987).

The spelling of 2542131535 in words is "two billion, five hundred forty-two million, one hundred thirty-one thousand, five hundred thirty-five".

Divisors: 1 5 47 235 947 4735 11423 44509 57115 222545 536881 2684405 10817581 54087905 508426307 2542131535