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254243513524963 is a prime number
BaseRepresentation
bin111001110011101110101110…
…010011110110001011100011
31020100012102221121010210210111
4321303232232103312023203
5231311011203430244323
62300421505132512151
7104360326163616634
oct7163565623661343
91210172847123714
10254243513524963
11740120832a7586
122462211a31b657
13abb30a2a72751
1446ad6476d988b
151e5d6cd2e4c0d
hexe73bae4f62e3

254243513524963 has 2 divisors, whose sum is σ = 254243513524964. Its totient is φ = 254243513524962.

The previous prime is 254243513524961. The next prime is 254243513525033. The reversal of 254243513524963 is 369425315342452.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 254243513524963 - 21 = 254243513524961 is a prime.

Together with 254243513524961, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 254243513524898 and 254243513524907.

It is not a weakly prime, because it can be changed into another prime (254243513524961) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127121756762481 + 127121756762482.

It is an arithmetic number, because the mean of its divisors is an integer number (127121756762482).

Almost surely, 2254243513524963 is an apocalyptic number.

254243513524963 is a deficient number, since it is larger than the sum of its proper divisors (1).

254243513524963 is an equidigital number, since it uses as much as digits as its factorization.

254243513524963 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 93312000, while the sum is 58.

The spelling of 254243513524963 in words is "two hundred fifty-four trillion, two hundred forty-three billion, five hundred thirteen million, five hundred twenty-four thousand, nine hundred sixty-three".