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254331201120119 is a prime number
BaseRepresentation
bin111001110101000000011000…
…111001011110011101110111
31020100111211021200211011210222
4321311000120321132131313
5231313430244441320434
62300530050230204555
7104366552154105254
oct7165003071363567
91210454250734728
10254331201120119
11740462906a4692
12246371107b375b
13abbb438798526
1446b39a545a42b
151e60b1164e72e
hexe75018e5e777

254331201120119 has 2 divisors, whose sum is σ = 254331201120120. Its totient is φ = 254331201120118.

The previous prime is 254331201120097. The next prime is 254331201120121. The reversal of 254331201120119 is 911021102133452.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 254331201120119 - 236 = 254262481643383 is a prime.

It is a super-2 number, since 2×2543312011201192 (a number of 30 digits) contains 22 as substring.

Together with 254331201120121, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (254331201120419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127165600560059 + 127165600560060.

It is an arithmetic number, because the mean of its divisors is an integer number (127165600560060).

Almost surely, 2254331201120119 is an apocalyptic number.

254331201120119 is a deficient number, since it is larger than the sum of its proper divisors (1).

254331201120119 is an equidigital number, since it uses as much as digits as its factorization.

254331201120119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 35.

The spelling of 254331201120119 in words is "two hundred fifty-four trillion, three hundred thirty-one billion, two hundred one million, one hundred twenty thousand, one hundred nineteen".