Search a number
-
+
254344100353139 is a prime number
BaseRepresentation
bin111001110101001100011001…
…110000001001010001110011
31020100120001120200000002222002
4321311030121300021101303
5231314133204142300024
62300540022221404215
7104400516624554516
oct7165143160112163
91210501520002862
10254344100353139
11740507aaa04345
122463971070966b
13abbc7130185a4
1446b446a674d7d
151e61118ce96ae
hexe75319c09473

254344100353139 has 2 divisors, whose sum is σ = 254344100353140. Its totient is φ = 254344100353138.

The previous prime is 254344100353099. The next prime is 254344100353141. The reversal of 254344100353139 is 931353001443452.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 254344100353139 - 28 = 254344100352883 is a prime.

Together with 254344100353141, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 254344100353093 and 254344100353102.

It is not a weakly prime, because it can be changed into another prime (254344100350139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127172050176569 + 127172050176570.

It is an arithmetic number, because the mean of its divisors is an integer number (127172050176570).

Almost surely, 2254344100353139 is an apocalyptic number.

254344100353139 is a deficient number, since it is larger than the sum of its proper divisors (1).

254344100353139 is an equidigital number, since it uses as much as digits as its factorization.

254344100353139 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2332800, while the sum is 47.

The spelling of 254344100353139 in words is "two hundred fifty-four trillion, three hundred forty-four billion, one hundred million, three hundred fifty-three thousand, one hundred thirty-nine".