Base | Representation |
---|---|
bin | 100101000000110100011… |
… | …011000010111100001101 |
3 | 100000011012220020212011202 |
4 | 211000310123002330031 |
5 | 313133042014110042 |
6 | 5224245015155245 |
7 | 351522206336012 |
oct | 45006433027415 |
9 | 10004186225152 |
10 | 2543500144397 |
11 | 8a0768582643 |
12 | 350b45075b25 |
13 | 155b0a951954 |
14 | 8b16b079709 |
15 | 46267a32632 |
hex | 250346c2f0d |
2543500144397 has 2 divisors, whose sum is σ = 2543500144398. Its totient is φ = 2543500144396.
The previous prime is 2543500144351. The next prime is 2543500144477. The reversal of 2543500144397 is 7934410053452.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2128079934436 + 415420209961 = 1458794^2 + 644531^2 .
It is a cyclic number.
It is not a de Polignac number, because 2543500144397 - 212 = 2543500140301 is a prime.
It is a super-3 number, since 3×25435001443973 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2543500143397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1271750072198 + 1271750072199.
It is an arithmetic number, because the mean of its divisors is an integer number (1271750072199).
Almost surely, 22543500144397 is an apocalyptic number.
It is an amenable number.
2543500144397 is a deficient number, since it is larger than the sum of its proper divisors (1).
2543500144397 is an equidigital number, since it uses as much as digits as its factorization.
2543500144397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1814400, while the sum is 47.
The spelling of 2543500144397 in words is "two trillion, five hundred forty-three billion, five hundred million, one hundred forty-four thousand, three hundred ninety-seven".
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