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2544130031 is a prime number
BaseRepresentation
bin1001011110100100…
…0101011111101111
320120022020012022012
42113221011133233
520202244130111
61100241311435
7120021514502
oct22751053757
96508205265
102544130031
111096105603
125b003557b
13317110ab1
141a1c5b139
15ed54648b
hex97a457ef

2544130031 has 2 divisors, whose sum is σ = 2544130032. Its totient is φ = 2544130030.

The previous prime is 2544130021. The next prime is 2544130033. The reversal of 2544130031 is 1300314452.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2544130031 - 214 = 2544113647 is a prime.

It is a super-2 number, since 2×25441300312 = 12945195229272121922, which contains 22 as substring.

Together with 2544130033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2544129979 and 2544130006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2544130033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1272065015 + 1272065016.

It is an arithmetic number, because the mean of its divisors is an integer number (1272065016).

Almost surely, 22544130031 is an apocalyptic number.

2544130031 is a deficient number, since it is larger than the sum of its proper divisors (1).

2544130031 is an equidigital number, since it uses as much as digits as its factorization.

2544130031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 2544130031 is about 50439.3698513374. The cubic root of 2544130031 is about 1365.1480973727.

Adding to 2544130031 its reverse (1300314452), we get a palindrome (3844444483).

The spelling of 2544130031 in words is "two billion, five hundred forty-four million, one hundred thirty thousand, thirty-one".