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2544321484097 is a prime number
BaseRepresentation
bin100101000001100101011…
…000001101010101000001
3100000020100010202020102122
4211001211120031111001
5313141232244442342
65224502315254025
7351551441531261
oct45014530152501
910006303666378
102544321484097
118a104a169288
1235113414a315
13155c0bb66983
148b20819b7a1
15462b4bc24d2
hex2506560d541

2544321484097 has 2 divisors, whose sum is σ = 2544321484098. Its totient is φ = 2544321484096.

The previous prime is 2544321484091. The next prime is 2544321484147. The reversal of 2544321484097 is 7904841234452.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2538639942721 + 5681541376 = 1593311^2 + 75376^2 .

It is a cyclic number.

It is not a de Polignac number, because 2544321484097 - 28 = 2544321483841 is a prime.

It is not a weakly prime, because it can be changed into another prime (2544321484091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1272160742048 + 1272160742049.

It is an arithmetic number, because the mean of its divisors is an integer number (1272160742049).

Almost surely, 22544321484097 is an apocalyptic number.

It is an amenable number.

2544321484097 is a deficient number, since it is larger than the sum of its proper divisors (1).

2544321484097 is an equidigital number, since it uses as much as digits as its factorization.

2544321484097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7741440, while the sum is 53.

The spelling of 2544321484097 in words is "two trillion, five hundred forty-four billion, three hundred twenty-one million, four hundred eighty-four thousand, ninety-seven".