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25492021981 is a prime number
BaseRepresentation
bin10111101111011100…
…010110001011011101
32102210120201220002021
4113233130112023131
5404201424200411
615413314300141
71561500416536
oct275734261335
972716656067
1025492021981
11a8a1644468
124b35287651
13253345719a
14133b86368d
159e2eb1a71
hex5ef7162dd

25492021981 has 2 divisors, whose sum is σ = 25492021982. Its totient is φ = 25492021980.

The previous prime is 25492021969. The next prime is 25492021993. The reversal of 25492021981 is 18912029452.

It is a balanced prime because it is at equal distance from previous prime (25492021969) and next prime (25492021993).

It can be written as a sum of positive squares in only one way, i.e., 13257449881 + 12234572100 = 115141^2 + 110610^2 .

It is a cyclic number.

It is not a de Polignac number, because 25492021981 - 29 = 25492021469 is a prime.

It is a super-2 number, since 2×254920219812 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25492021081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12746010990 + 12746010991.

It is an arithmetic number, because the mean of its divisors is an integer number (12746010991).

Almost surely, 225492021981 is an apocalyptic number.

It is an amenable number.

25492021981 is a deficient number, since it is larger than the sum of its proper divisors (1).

25492021981 is an equidigital number, since it uses as much as digits as its factorization.

25492021981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 43.

The spelling of 25492021981 in words is "twenty-five billion, four hundred ninety-two million, twenty-one thousand, nine hundred eighty-one".